Question 609930
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Hi
urn contains {{{18}}} balls:  5 yellow, 6 green and 7 blue balls
two balls are randomly drawn 'without' replacement
 A. P(both balls are green) = {{{(6/18)(5/17)}}}
 B. P(the first ball is blue and the second is yellow) = {{{(7/18)(5/17)}}}
 C. P(there is one green and one yellow ball)= 6C1*5C1/18C2 = 30/153 = 10/51