Question 609808
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Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case p & q are = 1/2 or .5
nCx = {{{n!/(x!(n-x)!)}}}  14C5 = 2002
P(5) =2002* {{{(.5)^5*(.5)^9}}} = .1222
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