Question 609604
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Sorry, but the answer depends on whether the variable is in the denominator or not.  Your rendering can be interpreted two ways:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ g(x)\ =\ \frac{5}{5}\ -\ 2x]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ g(x)\ =\ \frac{5}{5\ -\ 2x}]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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