Question 56436
Assume you mean:
:
{{{(4x-24)/(x^2-2x)}}} * {{{8x/(6-x)}}}
:
Do some factoring:
{{{(4(x-6))/(x(x-2))}}} * {{{8x/(6-x)}}}
:
In order to cancel the (x-6):
If we put -1 in front of the (6-x) we get -1(-6+x) which is -1(x-6)
so we can write it:
{{{(4(x-6))/(x(x-2))}}} * {{{8x/(-1(x-6))}}}
:
Cancel (x-6) and you have:
{{{4/(x(x-2))}}} * {{{8x/(-1)}}}={{{4/(x(x-2))}}} * - 8x =
:
{{{-32x/(x(x-2))}}} = {{{-32/(x-2)}}} (Canceled the x's)
:
Could you follow this oK?