Question 608899
Assume the problem is
{{{(x+3)/(x^2+x-2)}}} + {{{2/(x^2-1)}}} 
We can factor both denominators
{{{(x+3)/((x+2)(x-1))}}} + {{{2/((x-1)(x+1))}}} 
Common denominator is (x+2)(x-1)(x+1), multiply, combine like terms
{{{((x+1)(x+3) + 2(x+2))/((x+2)(x-1)(x+1))}}} = {{{((x^2+4x+3) + 2x+4)/((x+2)(x-1)(x+1))}}} = {{{(x^2+6x+7)/((x+2)(x-1)(x+1))}}}