Question 609090
Use the quadratic formula to solve for x.


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(5)+-sqrt((5)^2-4(1)(6)))/(2(1))}}}


{{{x = (-5+-sqrt(25-(24)))/(2)}}}


{{{x = (-5+-sqrt(1))/2}}}


{{{x = (-5+sqrt(1))/2}}} or {{{x = (-5-sqrt(1))/2}}}


{{{x = (-5+1)/2}}} or {{{x = (-5-1)/2}}}


{{{x = -4/2}}} or {{{x = -6/2}}}


{{{x = -2}}} or {{{x = -3}}}

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