Question 56512
simplify and reduce:
{{{(x^2+2x)/(4x-3)}}}/{{{6x^3/(8x^2-2x-3)}}}  Flip and multiply the second expression:
{{{((x^2+2x)/(4x-3))*((8x^2-2x-3)/(6x^3))}}}  Factor everything completely, I'm using the ac method for the trinomial:
{{{(x(x+2)/(4x-3))*((8x^2-6x+4x-3)/(x*6x^2))}}}  Since you see that an x was factored out of (x^2+2x), factor out an x from 6x^3, so that they can cancel.
{{{(x(x+2)/(4x-3))*((2x(4x-3)+1(4x-3))/(x*6x^2))}}}
{{{(x(x+2)/(4x-3))*((2x+1)(4x-3)/(x*6x^2))}}}  Cancel all the numerators and denominators that match each other:
{{{(cross((x))*(x+2)/cross((4x-3)))*((2x+1)*cross((4x-3))/(cross((x))*6x^2))}}}  Multiply what's left:
{{{highlight((x+2)(2x+1)/6x^2)}}}
Happy Calculating!!!