Question 608878
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<table border="1" cellpadding="2" cellspacing="2" width="60%">
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<th width="20%">Sum</th>
<th width="20%">Ways</th>
<th width="20%"># of Ways</th>
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<td width="20%">2</td><td width="20%">1,1</td><td width="20%">1</td>
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<td width="20%">3</td><td width="20%">1,2; 2,1</td><td width="20%">2</td>
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<td width="20%">4</td><td width="20%">1,3; 2,2; 3,1</td><td width="20%">3</td>
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<td width="20%">5</td><td width="20%">1,4; 2,3; 3,2; 4,1</td><td width="20%">4</td>
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<td width="20%">6</td><td width="20%">1,5; 2,4; 3,3; 4,2; 5,1</td><td width="20%">5</td>
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<td width="20%">7</td><td width="20%">1,6; 2,5; 3,4; 4,3; 5,2; 6,1</td><td width="20%">6</td>
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<td width="20%">8</td><td width="20%">2,6; 3,5; 4,4; 5,3; 6,2</td><td width="20%">5</td>
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<td width="20%">9</td><td width="20%">3,6; 4,5; 5,4; 6,3</td><td width="20%">4</td>
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<td width="20%">10</td><td width="20%">4,6; 5,5; 6,4</td><td width="20%">3</td>
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<td width="20%">11</td><td width="20%">5,6; 6,5</td><td width="20%">2</td>
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<td width="20%">12</td><td width="20%">6,6</td><td width="20%">1</td>
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The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.


If you add up the number of total ways that you can roll a pair of dice you get 36.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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