Question 608548
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From the coordinates of the center and the vertices/co-vertices, we can see that the center is at (3,2), the semi-major axis measures 6 (because the distance from (3,2) to (9,2) is 6) and the semi-minor axis measures 3 (because the distance from (3,2) to (3,5) is 3).  Furthermore the major axis is parallel to the *[tex \LARGE x]-axis (because the line through (3,2) and (9,2) is horizontal).


The equation of an ellipse centered at *[tex \LARGE (h,k)] with a semi-major axis that measures *[tex \LARGE a], a semi-minor axis that measures *[tex \LARGE b], and a major axis parallel to the *[tex \LARGE x]-axis is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(x\ -\ h)^2}{a^2}\ +\ \frac{(y\ -\ k)^2}{b^2}\ =\ 1]


Just plug in the numbers.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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