Question 608521
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Hi
Note: the vertex form of a parabola opening up or down, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
find the vertex of the following:
 y=(x-5)^2  {{{highlight(V(5,0))}}}
 y=(x+3)^2  {{{highlight(V(-3,0))}}}
 y=(x-1)^2  {{{highlight(V(1,0))}}}
 y=x^2+8    {{{highlight(V(0,8))}}}
 y=x^2-5    {{{highlight(V(0,-5))}}}
 y=x^2+2    {{{highlight(V(0,2))}}}