Question 608496
<pre>
An 8 sided die, which may or may not be a fair
die, has 4 colors on it; you have been tossing 
the die for an hour and have recorded the color 
rolled for each toss.  Using relative frequency 
what is the probability you will roll a brown 
on your next toss of the die?  

orange brown green yellow
  46     23    32    19

That's a total of 46+23+32+19 or 120 rolls.

You only asked for the probability of brown, 
but I'll give all the probabilities:

It came up orange 48 times out of 120, so the
experimental probability of orange is the
fraction {{{48/120}}} which reduces to {{{2/5}}}. 
Therefore the probability you will roll an 
orange on your next toss of the die is {{{2/5}}}.

It came up brown 23 times out of 120, so the
experimental probability of orange is the
fraction {{{23/120}}}, which doesn't reduce.
Therefore the probability you will roll a brown
on your next toss of the die is
{{{23/120}}}. (That's the answer to your problem).

It came up green 32 times out of 120, so the
experimental probability of orange is the
fraction {{{32/120}}} which reduces to{{{4/15}}}.
Therefore the probability you will
roll a green on your next toss of the die is
{{{4/15}}}.

It came up yellow 19 times out of 120, so the
experimental probability of orange is the
fraction {{{19/120}}} which doesn't reduce.
Therefore the probability you will
roll a yellow on your next toss of the die is
{{{19/120}}}.

Edwin</pre>