Question 608399
Find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function and graph the function.
f(x) = -2x^2 + 2x + 6
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This is a parabola that opens downwards:
Its standard form of equation: y=(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
y-coordinate of vertex is maximum value of function
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f(x)= -2x^2 + 2x + 6
complete the square
f(x)=-2(x^2-x+1/4)+6+1/2
f(x)=-2(x-1/2)^2+13/2
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Vertex: (1/2,13/2)
Line of symmetry: x=1/2
Maximum value=13/2
See graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,-2x^2 + 2x + 6) }}}