Question 608428
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Did you mean to say:


Solve for *[tex \Large a] in *[tex \Large b\ =\ \frac{3}{7}(a\ -\ 11)]?


Since that is the only thing that makes sense at this point:


Multiply both sides by *[tex \Large \frac{7}{3}]


Add *[tex \Large 11] to both sides.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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