<PRE><B>Question 608284</B>
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Substitute 0 for *[tex \LARGE y] then calculate the value of *[tex \LARGE x] that results.  Say that value is *[tex \LARGE a], then the *[tex \LARGE x]-intercept is the point *[tex \LARGE (a,0)]


Substitute 0 for *[tex \LARGE x] then calculate the value of *[tex \LARGE y] that results.  Say that value is *[tex \LARGE b], then the *[tex \LARGE y]-intercept is the point *[tex \LARGE (0,b)]


The values *[tex \LARGE a] and *[tex \LARGE b] will be ugly mixed number fractions in this problem.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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