Question 608203
<font face="Times New Roman" size="+2">

Let *[tex \LARGE x] represent the first of two consecutive integers, then *[tex \LARGE x\ +\ 1] represents the next consecutive integer.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(x\ +\ 1)\ =\ 506]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ x\ -\ 506\ =\ 0]


Solve for *[tex \LARGE x], discard any negative root, then calculate *[tex \LARGE x\ +\ 1].  Note that the coefficient on *[tex \LARGE x] is very small compared to the constant term.  Look for roots near the square root of the constant term.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>