Question 607865
That is exponential, not logarithmic.


If you know how to graph y = 3^x, this one is easy. The graph of (1/3)^x is simply an inverted y = 3^x (since 3^x = (1/3)^(-x)). Basically, reflect y = 3^x across the y-axis. However, the exponent is x-1, not x, so just shift the function one unit to the right. Final result should look something like this:


http://www.wolframalpha.com/input/?i=y+%3D+%281%2F3%29%5E%28x-1%29