<PRE><B>Question 608152</B>
an arrow is fired into the air with an initial velocity of 160 feet per second.  The height in feet of the arrow t seconds after it was shot into the air is given by the function h(t)= -16t^2+160t. find the maximum height of the arrow.
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The simplest way to do this is to find the 2 times when h = 0, at launch and at impact.
The time at max height is the average of the 2, or 1/2 the total time of flight.
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-16t^2+160t = 0
t = 0 (launch)
t = 10 (impact)
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h(t)= -16t^2+160t
Max ht is h(5)
= 400 feet
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