<PRE><B>Question 608148</B>
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You have two equations where *[tex \LARGE y] is equal to two different things.  Just set the two right-hand sides equal to each other and solve the resulting quadratic for *[tex \LARGE x].  Using the values you get for *[tex \LARGE x], you can calculate the two values for *[tex \LARGE y].


Note:  Roots will be complex.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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