Question 608023
cos^2 2x + 3sin2x = 3
-----------------
cos^2 = 1 - sin^2
1 - sin^2 + 3sin = 2
sin^2 - 3sin + 1 = 0
*[invoke solve_quadratic_equation 1,-3,1]
--------
sin(2x) =~ 0.381966 (Ignore the sin > 1 unless you want complex angles)
2x =~ 0.39192 + 2n*pi radians, n = 0,1,2,3...
x = 0.19596 radians + n*pi, n = 0,1,2,3...
x = pi - 0.19596 + n*pi, n = 0,1,2,3...