Question 607981
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Hi
standard deviation cannot be $2,750. If it were 275, for example:
{{{z =(22300 - 21500)/(275/sqrt(9000))}}}
 P( &#8804; to 22,3000) = P( z&#8804; .0366) = NORMSDIST(0.0366)= .5146
  .5146*9000= 4631 cars