Question 607678
model y=2e^kt where t is time in seconds
if there are 2 cells initially and 8 cells after 20 seconds, find the value of k for the bacteria
:
{{{2*e^(20k) = 8}}}
divide both sides by 2
{{{e^(20k) = 4}}}
using natural logs
20k = ln(4)
20k = 1.3863
k = {{{1.3963/20}}}
k = .0693
:
find how much bacteria is on the food after 5 seconds
y = {{{2*e^(5*.0693)}}}
y = 2.74 ~ 3 cells