Question 607753
1/x-3/4=x/4


4x(1/x)-4x(3/4)=4x(x/4)


4 - 3x = x^2


0 = x^2 + 3x - 4


x^2 + 3x - 4 = 0


(x+4)(x-1) = 0


x+4=0 or x-1=0


x = -4 or x = 1



So the solutions are x = -4 or x = 1

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