Question 607718
5x^2+2y^2+30x-16y=-67 


5x^2+30x+2y^2-16y=-67 


(5x^2+30x)+(2y^2-16y)=-67 


5(x^2+6x)+2(y^2-8y)=-67 


5(x^2+6x+9-9)+2(y^2-8y+16-16)=-67 


5((x^2+6x+9)-9)+2((y^2-8y+16)-16)=-67 


5((x+3)^2-9)+2((y-4)^2-16)=-67 


5(x+3)^2-5(9)+2(y-4)^2-2(16)=-67 


5(x+3)^2-45+2(y-4)^2-32=-67 


5(x+3)^2+2(y-4)^2-77=-67 


5(x+3)^2+2(y-4)^2=-67+77 


5(x+3)^2+2(y-4)^2=10


(5(x+3)^2)/10+(2(y-4)^2)/10=10/10


( (x+3)^2 )/2+( (y-4)^2 )/5 = 1


So this is an ellipse that is centered at (-3,4). 
It has a major axis that has a length of 2*sqrt(5) units and minor axis that has a length of 2*sqrt(2) units.



Note: the general form of an ellipse is ( (x-h)^2 )/(a^2)+( (y-k)^2 )/(b^2)=1


The center of this general ellipse is (h,k).
The length of the major axis of this general ellipse is 2a (where a > b)
The length of the minor axis of this general ellipse is 2b (where a > b)