Question 607530
{{{8x+x(x-2)=0}}}
{{{8x+x^2 - 2x=0}}}
{{{x^2 + 6x = 0}}}
x*(x + 6) = 0
x = 0 or x + 6 = 0
x = 0 or x = -6


The x intercepts of f(x)=8x+x(x-2) can be found by substituting f(x) with 0.
It will result the same equation as above, so the x intercepts of f(x)=8x+x(x-2) is (0, 0) and (-6, 0)