Question 607285
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
 f(x)= 4 +ln(3x) (Blue) |Domain x > 0 Asymptote is x = 0
 f^-1 = (1/3)e^(x-4)(Green    |x=4+ln(3y) , x-4 = ln(3y) and (1/3)e^(x-4)= f^-1 
{{{drawing(300,300,   -10,10,-10,10, 
 grid(1),
graph( 300, 300, -10,10,-10,10,0,4+ln(4x),(1/3)e^(x-4),x))}}}