Question 607184
4x+4y-mx-my


(4x+4y)+(-mx-my)


4(x+y)-m(x+y)


(4-m)(x+y)


So 4x+4y-mx-my completely factors to (4-m)(x+y)


In other words, 4x+4y-mx-my = (4-m)(x+y) for all values of m, x and y

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