Question 607170
Write an equation for a parabola with vertex at (3, -6) and focus at (3, -4)
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This is a parabola that opens upwards. (note the position of the focus in relation to the vertex)
Its standard form of equation: (x-h)^2=4p(y-k), (h,k) =(x,y) coordinates of vertex.
for given parabola:
given vertex(3,-6)
axis of symmetry: x=3
p=2 (distance from vertex to focus on axis of symmetry)
4p=8
equation: 
(x-3)^2=8(y+6)