Question 607153

{{{x^2+6x-16=0}}}.......we can write {{{6x}}} as {{{8x-2x}}}

{{{x^2+8x-2x-16=0}}}...now we can group first two and second two terms together

{{{(x^2+8x)+(-2x-16)=0}}}.......now, we want that minus sign to be in front of parentheses

{{{(x^2+8x)-(2x+16)=0}}}.....now, we are looking for common factors in both of the groups: in first group it is {{{x}}}, and in second group it is {{{2}}}....

{{{x(x+8)-2(x+8)=0}}}....now, we have common factor {{{x+8}}}

{{{(x+8)(x-2)=0}}}...these are simple factors of your equation, and solutions will be:


{{{x+8=0}}}....->...{{{x=-8}}}

{{{x-2=0}}}....->...{{{x=2}}}