Question 607114
<pre>
0,{{{1/4}}},{{{2/5}}},{{{3/6}}}

List the terms and the values for n:

n  nth term
1    0
2    {{{1/4}}}
3    {{{2/5}}}
4    {{{3/6}}}

Notice that in the 2nd, 3rd and 4th terms, the numerator
is 1 less than the value of n, and the denominator is 2
more than the value of n. 

That will also be the case with the first term if
we consider the 0 as {{{0/3}}} 

1    {{{0/3}}}
2    {{{1/4}}}
3    {{{2/5}}}
4    {{{3/6}}}

So the fifth term is {{{4/7}}}.  Therefore, the rule is

nth term = {{{(n-1)/(n+2)}}}

Edwin</pre>