Question 606965
{{{2x^2-x-2=0}}}

{{{2x^2-x=2}}}


/2

{{{x^2-(1/2)x=1}}}

Third term = (1/2* coefficient of middle term)^2
(1/2 * -1/2)^2=1/16

{{{x^2-(1/2)x+(1/16)=1+(1/16)}}}

{{{(x-(1/4))^2=17/16}}}

take the square root

x-(1/4) = +/-sqrt(17/16)

x= (1/4) +/-sqrt(17)/4)

x= 1.28 OR -0.78