Question 606591
At noon, car A is 41 miles due west of car B and traveling east at a constant speed of 55 miles an hour.
 Meanwhile, car B is traveling north at 40 miles per hour.
 At what time will the two cars be closest to each other?
:
the relationship between the two cars form a right triangle where
a = (41-55t), car a distance from reference point
b = 40t, car B travel distance from the the same point
c = distance between the cars at t time
:
c^2 = (41-55t)^2 + (40t)^2
c^2 = 1681 - 4510t + 3025t^2 + 1600t^2
c^2 = 4625t^2 - 4510t + 1681
c = {{{sqrt(4625t^2 - 4510t + 1681)}}}
Plot this equation
{{{ graph( 300, 200, -.5, 2, -5, 50, sqrt(4625x^2 - 4510x + 1681)) }}} 
looks like they will closest together in half an hour, about 24 miles