Question 606860
Solve the system
{{{x^2+y^2=100}}}
{{{y-x=2}}}


Solve the 2nd equation for y
{{{y-x=2}}}
{{{y=x+2}}}


So now you have
{{{x^2+y^2=100}}}
{{{y=x+2}}}


Now substitute the 2nd equation into the 1st one
{{{x^2+(x+2)^2=100}}}


Now expand and group like terms
{{{x^2+(x+2)^2=100}}}
{{{x^2+x^2+4x+4=100}}}
{{{2x^2+4x-96=0}}}


Now factor and solve
{{{2x^2+4x-96=0}}}
{{{2(x^2+2x-48)=0}}}
{{{2(x+8)(x-6)=0}}}


{{{x+8=0}}} {{{x-6=0}}}
{{{x=-8}}}    {{{x=6}}}