Question 606488
Suppose a child throws a ball upward and gives it an initial velocity of 10 feet per second. 
The starting height of the ball is 2.5 feet.
 How long will it take for the ball to reach its maximum height?
:
The formula for this:
f(t) = -16t^2 + 10t + 2.5
Where
f(t) = height after t time
-16t^2 = force of gravity downward
10t = initial velocity upward
2.5 = initial height of the ball
;
Find the max height, by finding the axis of symmetry: x = -b/(2a)
t = {{{(-10)/(2*-16) }}}
t = .3125 sec to reach max height