Question 606700
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
ln(3)-2(ln(4)+ln(8)  
ln(3)-ln(4^2)+ln(8)
ln (3·8/16) = ln(3/2)
Rules Governing Logarithms:
*[tex \large \ \  log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ] ***
*[tex \large\ \ log_bx + log_by = log_b(xy) ] ***
*[tex \large\ \ log_bx - log_by = log_b(x/y) ] ***
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ ln e^x = x]