Question 606647
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Hi,
Note: the vertex form of a parabola opening up or down, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex.
{{{y=x^2+5}}} tells us "h" = 0
Vertex is Pt(0,5)
{{{drawing(300,300,   -10,10,-10,10, 
 grid(1),
circle(0, 5,0.4),
graph( 300, 300, -10,10,-10,10,0,x^2+5))}}}