Question 606116
Write an equation for the parabola with focus (-1,1) and directrix y= -7.
This is an equation of a parabola that opens upwards.
Its standard form: (x-h)^2=4p(y-k)
for given parabola:
x-coordinate of vertex=-1
y-coordinate of vertex=(-7+1)/2=-3 (half way between focus and directrix on axis of symmetry)
vertex: (-1,-3)
axis of symmetry: x=-1
p=4 (distance from vertex to focus or directrix on the axis of symmetry)
4p=16
Equation:
(x+1)^2=16(y+3)