Question 606578
To make things a little easier, let's first get rid of the denominators by multiplying both sides of the equations (all terms) by 8 to get:
.
{{{8x = (8*w)/8+(8*y)/8 + (8*z)/8}}}
.
Where an 8 appears in the numerator, it cancels with the 8 in the denominator:
.
{{{8x = (cross(8)*w)/cross(8)+(cross(8)*y)/cross(8)+ (cross(8)*z)/cross(8)}}}
.
and we are left with:
.
{{{8x = w + y + z}}}
.
Now we want to get y by itself on one side of the equation and everything else on the other side. To do that we can subtract w and z from both sides of the equation:
.
{{{8x - w - z = w + y + z - w - z}}}
.
On the right side the w and the minus w cancel each other and also the z and the minus z cancel each other, and we are left with just y. So the equation is reduced to:
.
{{{8x - w - z = y}}}
.
Just transpose this (switch sides) to get it into the conventional form:
.
{{{y = 8x - w - z}}}
.
And that's the answer to this problem. We have solved for y in terms of the other variables in the equation.
.
Hope this helps you to understand what you were asked to do and how you would go about doing it.
.