Question 606133
how to graph 
x=y^2-6y+8
complete the square
x=(y^2-6y+9)+8-9
x=(y-3)^2-1
This is a parabola that opens rightwards
vertex: (-1,3)
x-intercept
set y=0
x=8
see graph below:
y=±(x+1)^.5+3
 {{{ graph( 300, 300, -10, 10, -10, 10, (x+1)^.5+3,-(x+1)^.5+3) }}}