Question 606016
*[tex \LARGE \frac{\cos(\frac{\pi}{2} - x) \tan{x}}{\sin^2{x}}]


Since cos (pi/2 - x) = sin x, the expression is equal to


*[tex \LARGE \frac{\sin{x} \tan{x}}{\sin^2{x}} = \frac{\tan{x}}{\sin{x}}]


By definition, tan x = sin x/cos x, replace tan x.


*[tex \LARGE = \cos{x}]