Question 606413
Evaluate:
{{{Log[10](0.001)}}} First, rewrite {{{0.001}}} as {{{10^(-3)}}}
{{{Log[10](10^(-3))}}} Now apply the "power rule" for logarithms: {{{Log[b](M^n) = n*Log[b](M)}}} to get:
{{{-3Log[10](10)}}} then substitute {{{Log[10](10) = 1}}}
{{{-3*1 = -3}}} so...
{{{Log[10](0.001) = -3}}}