Question 605865
The sum of three consecutive odd intergers is 24 more than the largest of the three intergers. Find the integers
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x=first odd integer
x+2=2nd odd integer
x+4=3rd odd integer
..
x+(x+2)+(x+4)=(x+4)+24
3x+6=x+28
2x=22
x=11
..
integers are: 11, 13 and 15