Question 605438
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If 35 have children and 15 have both pets and children then 35 minus 15 = 20 have only children.  Likewise, 7 have only pets.


So, 20 + 15 + 7 = 42 have either one or both, and 60 - 42 have neither.  From those values you can calculate either question A or question B.  Once you have either one, the probability of the other is 1 minus the probability of the first.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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