Question 605412
log(6x+3)=1+log(x-6)
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log(6x+3) - log(x-6) = 1
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log[(6x+3)/(x-6)] = 1
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(6x+3)/(x-6) = 10
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6x+3 = 10x-60
4x = 63
x = 63/4
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cheers,
Stan H.
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