Question 605340
y = 2*ln(x) + 6*log(2,x)


dy/dx = d/dx( 2*ln(x) + 6*log(2,x) )


dy/dx = d/dx( 2*ln(x) ) + d/dx( 6*log(2,x) )


dy/dx = 2*d/dx( ln(x) ) + 6*d/dx( log(2,x) )


dy/dx = 2*(1/x)+ 6*d/dx( ln(x)/ln(2) )


dy/dx = 2*(1/x)+ 6*(1/ln(2))*d/dx( ln(x) )


dy/dx = 2*(1/x)+ 6*(1/ln(2))*(1/x)


dy/dx = 2/x+ 6/(x*ln(2))



So the answer is {{{(dy)/(dx) = 2/x+ 6/(x*ln(2))}}}