Question 604570
the equations can be set up as $10x+$20y=300 and x+y=25 where x represents the $10 bills and y the $20 bills of we solve for x in the second one we get x=25-y and if we plug this in the first one we obtain... 10(25-y)+20y=300 then we start solving for y and obtain 250-10y+20y=300 which yields 10y=50 and y=5 which means there are 5 $20 bills and 20 $10 bills...