Question 605254
<pre>
kx³ - 8x² - x + (3k+1)

That means that when that is divided by x-2 the remainder = 0

Use synthetic division to divide by x-2 (you CAN use long division):

2| k    -8      -1     3k+1
 |<u>      2k    4k-16    8k-34</u>
   k   2k-8   4k-17   11k-33

So the remainder = 0

   11k - 33 = 0 
        llk = 33
          k = 3

Edwin</pre>