Question 55996
Divide and Simplify:
 
2x^2+11x+12/x^2-7x+10 divided by x^2+x-12/x^2-8x+15
: 
{{{(2x^2+11x+12)/(x^2-7x+10)}}}
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{{{(x^2+x-12)/(x^2-8x+15)}}}
Invert the dividing fraction and multiply:
{{{(2x^2+11x+12)/(x^2-7x+10)}}}*{{{(x^2-8x+15)/(x^2+x-12)}}}
:
Factor each quadratic:
{{{(2x+3)(x+4)/(x-5)(x-2)}}}*{{{(x-5)(x-3)/(x-3)(x+4)}}}
:
Note that you can cancel (x+4), (x-5), and (x-3), this leaves you with:
{{{(2x+3)/(x-2)}}}