Question 604773


{{{x^2-36y^2}}} Start with the given expression.



{{{(x)^2-36y^2}}} Rewrite {{{x^2}}} as {{{(x)^2}}}.



{{{(x)^2-(6y)^2}}} Rewrite {{{36y^2}}} as {{{(6y)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=x}}} and {{{B=6y}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(x)^2-(6y)^2=(x+6y)(x-6y)}}} Plug in {{{A=x}}} and {{{B=6y}}}.



So this shows us that {{{x^2-36y^2}}} factors to {{{(x+6y)(x-6y)}}}.



In other words {{{x^2-36y^2=(x+6y)(x-6y)}}}.