Question 604741
{{{9^sqrt(x)}}} = {{{3^x}}}
9 = 3^2, therefore we can rewrite this to
{{{3^(2sqrt(x))}}} = {{{3^x}}}
therefore
{{{2sqrt(x)}}} = x
Square both sides to get rid of the radical
4x = x^2
0 = x^2 - 4x
or
x^2 - 4x = 0
Factor 
x(x-4) = 0
two solutions
x = 0
and 
x = 4