Question 56233
x^2+2x-15/4x^2 Divided by x^2-25/2x-10 
Factor where you can:
[(x-5)(x+3)]/4x^2 divided by [(x-5)(x+5)]/2(x-5)
Cancel the (x-5)'s in the denominator to get:
[(x-5)(x+3)]/4x^2 divided by (x+5)/2
Now, invert the denominator and multiply to get:
[(x-5)(x+3)]/4x^2 multiplied by 2/(x+5)
Cancel the common factor of "2" to get:
[(x-5)(x+3)]/[2x^2(x+5)]
Cheers,
Stan H.